-16x^2+45x+10=0

Solution for -16x^2+45x+10=0 equation:

-16x^2+45x+10=0

a = -16; b = 45; c = +10;
Δ = b2-4ac
Δ = 452-4·(-16)·10
Δ = 2665
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{2665}}{2*-16}=\frac{-45-\sqrt{2665}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{2665}}{2*-16}=\frac{-45+\sqrt{2665}}{-32}
$